Code with Finding: |
class Query {
/** Expert: called when re-writing queries under MultiSearcher.
*
* Create a single query suitable for use by all subsearchers (in 1-1
* correspondence with queries). This is an optimization of the OR of
* all queries. We handle the common optimization cases of equal
* queries and overlapping clauses of boolean OR queries (as generated
* by MultiTermQuery.rewrite()).
* Be careful overriding this method as queries[0] determines which
* method will be called and is not necessarily of the same type as
* the other queries.
*/
public Query combine(Query[] queries) {
HashSet uniques = new HashSet();
for (int i = 0; i < queries.length; i++) {
Query query = queries[i];
BooleanClause[] clauses = null;
// check if we can split the query into clauses
boolean splittable = (query instanceof BooleanQuery);
if(splittable){
BooleanQuery bq = (BooleanQuery) query;
splittable = bq.isCoordDisabled();
clauses = bq.getClauses();
for (int j = 0; splittable && j < clauses.length; j++) {
splittable = (clauses[j].getOccur() == BooleanClause.Occur.SHOULD);
}
}
if(splittable){
for (int j = 0; j < clauses.length; j++) {
uniques.add(clauses[j].getQuery());
}
} else {
uniques.add(query);
}
}
// optimization: if we have just one query, just return it
if(uniques.size() == 1){
return (Query)uniques.iterator().next();
}
Iterator it = uniques.iterator();
BooleanQuery result = new BooleanQuery(true);
while (it.hasNext())
result.add((Query) it.next(), BooleanClause.Occur.SHOULD);
return result;
}
}
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